Metoda nextInt() klase Random vraća sljedeću pseudoslučajnu, ravnomjerno raspodijeljenu int vrijednost iz niza generatora slučajnih brojeva.
Sintaksa
public int nextInt()
Parametri
DA
Povratna vrijednost
Metoda nextInt() vraća sljedeću pseudoslučajnu int vrijednost izvučenu iz niza generatora slučajnih brojeva.
Primjer 1
import java.util.Random; public class JavaRandomNextIntExample1 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(); System.out.println('Random Integer value : '+val); Integer val1 = random.nextInt(); System.out.println('Random Integer value : '+val1); } } Testirajte sada Izlaz:
Random Integer value : -298063488 Random Integer value : 1400961289
Java Random nextInt() metoda
Metoda nextInt(int n) klase Random vraća pseudoslučajnu int vrijednost između nule (uključivo) i navedene vrijednosti (isključivo), izvučenu iz niza generatora slučajnih brojeva.
Sintaksa
public int nextInt(int n)
Parametri
n : To je granica slučajnog broja koji se vraća. Mora biti pozitivan.
Povratna vrijednost
Metoda nextInt() vraća sljedeću pseudoslučajnu int vrijednost između nula i n izvučenu iz niza generatora slučajnih brojeva.
Bacanja
Metoda nextInt() izbacuje IllegalArgumentException ako n nije pozitivan.
Primjer 2
import java.util.Random; public class JavaRandomNextIntExample2 { static int j=1; public static void main(String[] args) { Random random = new Random(); for (int i=1;i<8;i++) { return the next pseudorandom integer value val="random.nextInt(i);" system.out.println(j++ +'. random intvalue : '+val+' '); } < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> 1. Random intvalue : 0 2. Random intvalue : 1 3. Random intvalue : 0 4. Random intvalue : 3 5. Random intvalue : 1 6. Random intvalue : 0 7. Random intvalue : 0 </pre> <h2>Example 3</h2> <pre> import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + ' '); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +'. +xyz+' will have '+val+' bonus points.'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;></pre></8;i++)> Primjer 3
import java.util.Random; import java.util.Scanner; import java.util.concurrent.ArrayBlockingQueue; public class JavaRandomNextIntExample3 { static int j=1; public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter number of players.'); int capacity = scanner.nextInt(); ArrayBlockingQueue queue = new ArrayBlockingQueue(capacity); System.out.println('Enter name of ' + capacity + ' Players.'); for (int i = 0; i <capacity; i++) { system.out.print(j++ + \' \'); string str="scanner.next();" queue.add(str); } j="1;" random random(); for (string xyz : queue) integer val="random.nextInt(capacity);" system.out.println(j++ +\'. +xyz+\' will have \'+val+\' bonus points.\'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter number of players.3 Enter name of 3 Players. 1 Sukla 2 Mukta 3 Amar 1. Sukla will have 0 bonus points. 2. Mukta will have 1 bonus points. 3. Amar will have 2 bonus points. </pre> <h2>Example 4</h2> <pre> import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9) </pre> <h4>Note: The bound value must be positive else it will give IllegalArgumentException.</h4></capacity;> Primjer 4
import java.util.Random; public class JavaRandomNextIntExample4 { public static void main(String[] args) { Random random = new Random(); //return the next pseudorandom integer value Integer val = random.nextInt(0); System.out.println('Random Integer value : '+val); } } Testirajte sada Izlaz:
Exception in thread 'main' java.lang.IllegalArgumentException: bound must be positive atjava.util.Random.nextInt(Random.java:388) at com.javaTpoint.JavaRandomNextIntExample4.main(JavaRandomNextIntExample4.java:9)