The nastavak izjave u jeziku C koristi se za dovođenje programske kontrole na početak petlje. Naredba continue preskače neke retke koda unutar petlje i nastavlja sa sljedećom iteracijom. Uglavnom se koristi za uvjet tako da možemo preskočiti neki kod za određeni uvjet.

Sintaksa:

 //loop statements continue; //some lines of the code which is to be skipped 

Nastavite primjer izjave 1

 #include void main () { int i = 0; while(i!=10) { printf('%d', i); continue; i++; } } 

Izlaz

 infinite loop 

Nastavite primjer izjave 2

 #include int main(){ int i=1;//initializing a local variable //starting a loop from 1 to 10 for(i=1;i<=10;i++){ if(i="=5){//if" value of i is equal to 5, it will continue the loop continue; } printf('%d 
',i); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 2 3 4 6 7 8 9 10 </pre> <p>As you can see, 5 is not printed on the console because loop is continued at i==5.</p> <h2>C continue statement with inner loop</h2> <p>In such case, C continue statement continues only inner loop, but not outer loop.</p> <pre> #include int main(){ int i=1,j=1;//initializing a local variable for(i=1;i<=3;i++){ for(j="1;j&lt;=3;j++){" if(i="=2" && j="=2){" continue; will continue loop of only } printf('%d %d
',i,j); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 1 1 2 1 3 2 1 2 3 3 1 3 2 3 3 </pre> <p>As you can see, 2 2 is not printed on the console because inner loop is continued at i==2 and j==2.</p> <hr></=3;i++){></pre></=10;i++){>

Kao što vidite, 5 se ne ispisuje na konzoli jer se petlja nastavlja na i==5.

C naredba continue s unutarnjom petljom

U tom slučaju C naredba continue nastavlja samo unutarnju petlju, ali ne i vanjsku petlju.

 #include int main(){ int i=1,j=1;//initializing a local variable for(i=1;i<=3;i++){ for(j="1;j&lt;=3;j++){" if(i="=2" && j="=2){" continue; will continue loop of only } printf(\'%d %d
\',i,j); end for return 0; < pre> <p> <strong>Output</strong> </p> <pre> 1 1 1 2 1 3 2 1 2 3 3 1 3 2 3 3 </pre> <p>As you can see, 2 2 is not printed on the console because inner loop is continued at i==2 and j==2.</p> <hr></=3;i++){>

Kao što vidite, 2 2 se ne ispisuje na konzoli jer se unutarnja petlja nastavlja na i==2 i j==2.